The arrow is fired from the bow vertically upward at a speed of 45 m / s. after what time did the arrow fall to the ground?

Given:

v = 45 m / s (meters per second) – initial velocity of an arrow fired vertically upward from a bow.

It is required to determine t (seconds) – the time after which the arrow will fall to the ground.

Taking into account the fact that at the maximum height the speed of the arrow will be equal to zero, we find the time for which the arrow will rise up:

t1 = v / g, where g = 9.8 Newton / kilogram;

t1 = 45 / 9.8 = 4.6 seconds (the result has been rounded to one decimal place).

Since the fall time is equal to the rise time, we get that:

t = 2 * t1 = 2 * 4.6 = 9.2 seconds.

Answer: The arrow fell to the ground 9.2 seconds after the start of the movement.