The arrow is released vertically upward at a speed of 50 m / s. After 3 seconds, it hits the target.

The arrow is released vertically upward at a speed of 50 m / s. After 3 seconds, it hits the target. At what height was the target and what is the speed of the arrow at the moment it hits the target?

Data: V1 (boom speed at the moment of starting up) = 50 m / s; t (flight time before hitting the target) = 3 s.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

1) The height at which the target was (distance traveled by the arrow): S = H = V1 * t – 0.5 * g * t ^ 2 = 50 * 3 – 0.5 * 10 * 3 ^ 2 = 150 – 45 = 105 m.

2) The speed of the arrow at the moment of hitting the target: V2 = V1 – g * t = 50 – 10 * 3 = 50 – 30 = 20 m / s.

Answer: The target was at a height of 105 meters, the arrow hit it at a speed of 20 m / s.