# The arrow was fired vertically upward with an initial speed of 35 m / s.

**The arrow was fired vertically upward with an initial speed of 35 m / s. If we neglect the air resistance, then 3 seconds after the shot, the arrow speed is?**

Given:

v0 = 35 m / s (meters per second) – the initial velocity of the arrow released vertically upward;

t = 3 seconds – time span.

It is required to determine v (m / s) – the speed of the arrow after a time interval equal to t.

By the condition of the problem, we neglect the air resistance. Then, since the initial speed of the arrow is directed upward, and the acceleration of gravity is directed downward, to determine the speed, you must use the following formula:

v = v0 – g * t, where g = 9.8 m / s2;

v = 35 – 9.8 * 3 = 35 – 29.4 = 5.6 m / s.

Answer: Three seconds after the start of movement, the arrow speed will be 5.6 meters per second.