The arrow was launched from a flat horizontal surface of the earth at an angle to the horizon and fell after 4 seconds

The arrow was launched from a flat horizontal surface of the earth at an angle to the horizon and fell after 4 seconds at what distance from the shot did the arrow fall if 2 seconds after its shot its speed is 50 m / s

Given:

t1 = 4 s – total flight time;

v (2) = 50 m / s – arrow speed after 2 seconds.

It is required to find L (m), the distance that the arrow flew.

Since the full flight time is 4 seconds, this means that the arrow went up for 2 seconds, and another 2 seconds fell. That is, after 2 seconds the arrow was at its maximum height, where the vertical component of the velocity was absent, and the horizontal one was equal to v (2). The horizontal speed is constant throughout the flight and does not change, therefore:

L = v (2) * t1 = 50 * 4 = 200 meters.

Answer: the arrow has flown a distance of 200 meters.