The artist jumped onto the net at a speed of 9 m / s until the net came to a complete stop, the net stretched

The artist jumped onto the net at a speed of 9 m / s until the net came to a complete stop, the net stretched for 1.5 meters. Find the acceleration of deceleration.

To find the acceleration of the artist’s deceleration after the jump, we will use the formula: S = Vn ^ 2 / 2a and a = Vn ^ 2 / 2S.

Variables: Vн – jump speed of the artist (Vн = 9 m / s); S – stretching of the net, artist’s path (S = 1.5 m).

Calculation: a = Vn ^ 2 / 2S = 9 ^ 2 / (2 * 1.5) = 27 m / s2.

Answer: The artist’s deceleration acceleration was 27 m / s2.