The athlete lifted a barbell weighing 80 kg. How much has the athlete’s pressure on the floor increased

The athlete lifted a barbell weighing 80 kg. How much has the athlete’s pressure on the floor increased if the total area of the soles of his boots is 600 cm ^ 2?

To determine the increase in the athlete’s pressure on the floor, we will use the formula: P = ΔF / S = Δm * g / S.

Variables and constants: Δm – an increase in the athlete’s weight, the weight of the bar (Δm = 80 kg); g – acceleration due to gravity (g ≈ 10 m / s2); S – the total area of the soles of the athlete’s shoes (S = 600 cm2 = 600 * 10 ^ -4 m2).

Calculation: P = Δm * g / S = 80 * 10 / (600 * 10 ^ -4) = 13.33 * 10 ^ 3 Pa = 13.33 kPa.

Answer: The pressure of the athlete on the floor increased by 13.33 kPa.