The average data transfer rate over a certain communication channel is 29 Kbps. How many seconds

The average data transfer rate over a certain communication channel is 29 Kbps. How many seconds will it take to transmit 50 pages of text over this channel if you count that one character is encoded in one byte and on each page there are an average of 96 characters?

First, you need to determine the total number of characters in the file.

To do this, we multiply the specified number of pages among ourselves by the number of characters per page.

We get:

50 * 96 = 4800.

1 byte contains 8 bits.

Since one character takes 1 byte, the file size in bits is:

4800 * 8 = 38400 bits.

Since there are 1024 bits in 1 kilobit, the transmission speed will be equal to:

29 * 1024 = 29696 bps.

This means that you will need to transfer the file:

38400/29696 = 1.29 seconds.

Answer: It will take 1.29 seconds.