The average data transfer rate over a certain communication channel is 30 kbps. Determine how many seconds it will

The average data transfer rate over a certain communication channel is 30 kbps. Determine how many seconds it will take to transmit 80 pages of text over this channel, each page of which contains an average of 120 characters, and the information weight of one character is 8 bits.

To solve this problem, you first need to determine the total number of characters in this text.

To do this, we multiply the known number of pages among ourselves by the specified number of characters per page.

We get:

120 * 80 = 9600 characters.

Determine the information volume of the file.

Since the character size is 8 bits, the entire file will take up:

9600 * 8 = 76800 bits.

We translate the transmission rate of the communication channel into bit / s.

30 * 1024 = 30720.

From this it follows that the file transfer time will be:

76800/30720 = 2.5 seconds.

Answer: 2.5 s.