The average satellite height above the earth’s surface is 300 km. Find his speed.

Given:
h = 300 (km)
Rз earth radius = 6371 (km)
Mz earth mass = 5.976 * 10 ^ 24 (km)
G (gravitational constant) = 6.673 * 10 ^ -11 (H * m ^ 2 * kg ^ -2)
v (satellite rotation speed) =? (km / s)
Solution by the formula: v = sqrt (G * (Mz / (Rz + h)), then
v = sqrt ((6.673 * 10 ^ -11) * ((5.976 * 10 ^ 24) / (6.371 * 10 ^ 6 + 3 * 10 ^ 5))) =
7731.6179648486 = 7.7 (km / s)
Answer: v = 7.7 (km / s)