The axial section of the cylinder is a rectangle with an area of 48 square meters. Calculate the total surface

The axial section of the cylinder is a rectangle with an area of 48 square meters. Calculate the total surface area if its height is 6 m.

Since the axial section ABCD is a rectangle, then Ssec = AB * AD.

AD = Ssection / AB = 48/6 = 8 m.

AD is the diameter of the circle at the base of the cylinder, then R = AD / 2 = 8/2 = 4 m.

Determine the area of the base of the cylinder. Sop = π * R ^ 2 = 16 * π m2.

The area of the lateral surface of the cylinder is: Sside = 2 * π * R * AB = 2 * π * 4 * 6 = 48 * π m2.

Then Sпов = 2 * Sсн + Sbok = 2 * 16 * π + 48 * π = 80 * π m2.

Answer: The total surface area of the cylinder is 80 * π m2.



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