The axial section of the cylinder is a square, find the area of this section if the area of the base of the cylinder is 13п

It is known that a circle lies at the base of the cylinder, we also know the area of this base 13n, we write down what this area is equal to in our case:
S = nR ^ 2 = 13n.
R = (S / n) ^ (1/2).
R = (13p / n) ^ (1/2) = √13.
Let’s find now the length of the base diameter:
d = 2R = 2√13 cm.
The length of the diameter is equal to the length of the height of the cylinder, since it is said that the axial section is a square, then the section area will be equal to:
S1 = d ^ 2 = (2√13) ^ 2 = 52 cm2.
Answer: the area of the axial section of this cylinder is 52 cm2.