The axial section of the cylinder is a square, the area of which is 196 cm ^ 2. Find the area of the base

The axial section of the cylinder is a square, the area of which is 196 cm ^ 2. Find the area of the base of the cylinder and the diagonal of its axial section.

Since the axial section of the cylinder is a square, the height of the AB cylinder is equal to the diameter of the AD circle at the bases of the cylinder.

Ssection = 196 = AB * AD = AB ^ 2.

AB = AD = 14 cm.

The AC diagonal forms an isosceles right-angled triangle ABC.

Then AC ^ 2 = 2 * AB ^ 2 = 2 * 196 = 39 ^ 2.

AC = 14 * √2 cm.

Determine the area of the base of the cylinder.

Sb = π * АD ^ 2/4 = π * 49 cm2.

Answer: The area of the base is π * 49 cm2, the diagonal of the axial section is 14 * √2 cm.



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