The axial sectional area of the cylinder is 12п dm2, and the base area is 64dm2, find the height of the cylinder?

Knowing the area of the base of the cylinder, we determine the radius of the circle at its base.
Sop = π * R ^ 2.
R ^ 2 = Sb / π.
R ^ 2 = 64 / π.
R = 8 / √π dm.
Then the diameter of the circle at the base of the cylinder is: D = AD = 2 * R = 16 / √π dm.
The axial section of the cylinder is a rectangle ABCD, then Ssec = AB * AD.
AB = h = Ssection / BP = 12 * √π / (16 / √π) = 12 * π / 16 = 3 * π / 4 dm2.
Answer: The height of the cylinder is 3 * π / 4 dm2.