The ball begins to move up an inclined plane with an initial speed of 10m / s

| February 24, 2021 | education

The ball begins to move up an inclined plane with an initial speed of 10m / s and an acceleration of 2m / s. What path will the ball cover to stop?

V0 = 10 m / s.

V = 0 m / s.

a = 2 m / s2.

S -?

When braking with constant acceleration, the path S traversed by the body is determined by the formula: S = V0 * t – a * t2 / 2, where V0 is the initial speed of movement, t is the braking time, a is the acceleration during braking.

The braking time t is expressed from the formula for the acceleration of the body a: a = (V0 – V) / t.

Since the body at the end stopped V = 0 m / s, the formulas will take the form: a = V0 / t.

t = V0 / a.

t = 10 m / s / 2 m / s2 = 5 s.

S = 10 m / s * 5 s – 2 m / s2 * (5 s) 2/2 = 25 m.

Answer: the ball will travel S = 25 m until it comes to a complete stop.



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