The ball falls to the ground from a height of 25 m without initial speed. How high will the ball be in 1 s?

Problem data: h (initial height of the considered ball) = 25 m; the ball fell without initial velocity (V0 = 0 m / s); t1 (time elapsed since the beginning of the fall) = 1 s.

Reference values: g (acceleration of gravity, acceleration of the ball) ≈ 10 m / s2.

The height of the ball in question after 1 s fall is determined by the formula: h2 = h – h1 = h – 0.5 * g * t1 ^ 2.

Let’s perform the calculation: h2 = 25 – 0.5 * 10 * 1 ^ 2 = 25 – 5 = 20 m.

Answer: After 1 s, the ball in question will be at a height of 20 m.