The ball fell from a height of 2 meters, bounced by 1 m, fell again and jumped to a height of 0.8 m, where

The ball fell from a height of 2 meters, bounced by 1 m, fell again and jumped to a height of 0.8 m, where it was caught. Find the path and module of the displacement vector.

h0 = 2 m.

h1 = 1 m.

h2 = 0.8 m.

L -?

S -?

The distance traveled by the ball L is the length of the line that it describes when it moves.

Let us express the path of the ball L by the formula: L = h0 + h1 + h1 + h2.

L = 2 m + 1 m + 1 m + 0.8 m = 4.8 m.

The movement of the body S is called a vector that connects the initial and final positions of the body during movement.

The initial position of the body was at a height of h0, and the final position of the body was at a height of h2, so the movement of the ball S is expressed by the formula: S = h0 – h2.

S = 2 m – 0.8 m = 1.2 m.

Answer: when moving, the ball traveled a path L = 4.8 m and made a movement S = 1.2 m.