The ball fell from a height of 2m and after hitting the floor jumped 1m. Find the path of the ball and the module of movement.

| December 3, 2020 | education

1. The ball fell from a height of 2m and after hitting the floor jumped 1m. Find the path of the ball and the module of movement. 2. The car moves at a speed of 62.8 km / h along a ring road with a radius of 5 km. What is the period of revolution? 2. The boy on the balcony released a pebble, and after 0.5 seconds a ball. What is the speed of the pebble relative to the ball after another 0.5 s? 3. Having run along the runway 2.4 km, the plane acquired a speed of 80 m / s. How long did the run take?

1. The path is equal: L = 3m. Since displacement is the distance between the initial and final positions of the body, then: S = 1m.
2. The linear velocity of the body is equal to: V = 2pi R / T, so the period is equal to: T = 1 h
3. After 0.5 s the speed of the ball will be: Vm = 10 * 0.5 = 5m / s
After 1s the speed of the stone:
Vk = 10m / s
So the speed of the pebble relative to the ball is: V = 5m / s
4. The takeoff run is: S = Vt / 2, which means the time is: t = 60s



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