The ball is acted upon by the force of gravity of 10 N, and the mass of the cylinder

The ball is acted upon by the force of gravity of 10 N, and the mass of the cylinder is 50 g. How many times is the force of gravity acting on the ball?

Given:

F1 = 10 Newton – the force of gravity acting on the ball;

m2 = 50 grams – cylinder mass;

g = 10 Newton / kilogram – acceleration of gravity (constant value near the earth’s surface).

It is required to determine F1 / F2 – how many times the force of gravity acting on the ball is greater than the force of gravity acting on the cylinder.

Let’s convert mass units from grams to kilograms:

m2 = 50 grams = 50 * 10-3 = 0.05 kilograms.

Then the force of gravity acting on the cylinder is:

F2 = m2 * g = 0.05 * 10 = 0.5 Newton.

F1 / F2 = 10 / 0.5 = 20 times.

Answer: the ball is affected by 20 times the force of gravity.