The ball is thrown at an initial speed of 20 meters. The flight range of the ball at a throwing angle of 30 degrees is equal to.
| January 20, 2021 | education
The horizontal component of the ball speed:
Vx = V0 × cos α = 20 × cos (30o) = 17.32 m / s.
Initial vertical component of speed:
Vz0 = V0 × sin α = 20 × sin (30o) = 10.00 m / s.
Time to lift the ball to the highest point of the trajectory:
t1 = Vz0 / g = 10 / 9.8 = 1.02 s.
The time it takes for the ball to rise to its highest point is equal to the time it takes it to land.
Total flight time of the ball:
t = 2 t1 = 2 × 1.02 = 2.04 s.
Ball flight range:
L = Vх t = 17.32 × 2.04 = 35.33 m.
Answer: 35.33 m.
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