The ball is thrown from a height of h = 10 m Throw 3 times: 1) vertically down 2) vertically up 3) horizontally forward.

The ball is thrown from a height of h = 10 m Throw 3 times: 1) vertically down 2) vertically up 3) horizontally forward. When will the ball reach its maximum speed when it hits the ground?

1. For a body thrown vertically upwards according to the law of conservation of energy:
Ep + Ek = Ep1 + Ek1
We have the potential energy of the body at the moment of contact with the Earth = 0
Ep + Ek = Ek1
Now let’s write in expanded form:
mgh + mv0² / 2 = m1v1² / 2
2. For a body thrown down:
Ep + Ek = Ek2
Now let’s write in expanded form:
mgh + mv0² / 2 = m1v2² / 2
3. For a body thrown horizontally forward:
Ep + Ek = Ek3
Now let’s write in expanded form:
mgh + mv0² / 2 = m1v3² / 2
To compare the speed from these expressions, it makes no sense, because these laws are the same, then the obtained speeds will be the same.
Answer: the speed on contact with the Earth will be the same.