The ball is thrown horizontally from a height of 5 m with an initial speed of 15 m / s.

The ball is thrown horizontally from a height of 5 m with an initial speed of 15 m / s. Determine the time and distance of the balloon flight?

h = 5 m.

V0 = 15 m / s.

g = 10 m / s2.

t -?

L -?

The motion of the ball can be divided into two types: horizontally, it moves uniformly with a speed V0, vertically uniformly accelerated with an acceleration of gravity g without an initial velocity.

The flight range L is expressed by the formula: L = V0 * t, where V0 is the ball throwing speed, t is the ball flight time.

Let us express the time t of the ball falling from the height h from the formula: h = g * t ^ 2/2.

t = √ (2 * h / g).

t = √ (2 * 5 m / 10 m / s2) = 1 s.

L = 15 m / s * 1 s = 15 m.

Answer: the flight range of the ball is L = 15 m, the flight time of the ball is t = 1 s.