The ball is thrown horizontally from the window with a speed v0 = 10m / s. At what distance will

The ball is thrown horizontally from the window with a speed v0 = 10m / s. At what distance will the ball fall if the window is at a height of 45 m?

Neglecting the air resistance, we find that the horizontal movement of the ball is uniform, and the vertical movement is uniformly accelerated, with an acceleration g = 9.8 m / s2 directed vertically downward.

Equation of vertical motion of the ball:

H = g t ^ 2/2,

where H is the initial height of the ball above ground level, H = 45 m; t is the time of the ball falling, s.

Ball fall time: t = (2 H / g) ^ 1/2.

Since the horizontal speed of the ball is constant, the distance L is equal to:

L = V0 t = V0 (2 H / g) ^ 1/2 = 10 × (2 × 45 / 9.8) ^ 1/2 = 30.3 m.