Initial data: V0 (the speed with which the ball was thrown from the surface of the Earth) = 5 m / s; V (the speed that the ball must reach) = 2 m / s; a (acceleration with which the ball will move, slow motion) = -g (acceleration of gravity) = 10 m / s ^ 2.
The height at which the speed of the ball becomes 2 m / s is determined by the formula: H = (V ^ 2 – V0 ^ 2) / 2a = (V ^ 2 – V0 ^ 2) / (-2g) = (V0 ^ 2 – V ^ 2) / 2g.
Let’s perform the calculation: H = (5 ^ 2 – 2 ^ 2) / (2 * 10) = 1.05 m.
Answer: The ball rises to a height of 1.05 m.
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