The ball is thrown vertically downward at a speed, the modulus of which is 4.0 m / s, from a height of 1.0 m.

The ball is thrown vertically downward at a speed, the modulus of which is 4.0 m / s, from a height of 1.0 m. Determine the height at which the ball will be after hitting the floor. Disregard energy losses on impact.

According to the law of conservation of energy (since losses are not taken into account), after the reflection from the floor, reaching a height of 1 m, the ball will have the same speed equal to 4.0 m / s. Let’s use the formula to determine the maximum height of a body thrown vertically to the top: h = v0 ^ 2/2 * g, where v0 is the initial velocity, g is the acceleration of gravity.

h = 4.0 ^ 2/2 * 10 = 16/20 = 0.8 m.

Then the height relative to the ground will be:

1 + 0.8 = 1.8 m.

Answer: the ball will be at a height of 1.8 m.