The ball is thrown vertically upward at a speed of 8 m / s. What is the maximum height it will climb? How long will it fly?

Given:
v0 = 8m / s;
Find: H -? t -?
Let us write the equation for uniformly accelerated motion along the y coordinate:
y = v0 * t – 1/2 * g * t ^ 2;
here
g = 10m / s ^ 2 – free fall acceleration;
Since at the end of the flight the ball coordinate
y = 0,
then from the equation we obtain
v0 * t = 1/2 * g * t ^ 2;
Where can we find the flight time of the ball:
t = 2 * v0 / g;
t = 2 * 8/10 = 1.6s.
The equation of uniformly accelerated motion can be written in the following form:
y = [(v0) ^ 2 – (v) ^ 2] / (2 * g),
Where
vy is the speed of the ball at the point y;
Since at the highest point y = H the speed is v = 0, we get:
H = 1 / (2 * g) * (v0) ^ 2 = 1/20 * 64 = 3.2m.