The ball is thrown vertically upward at a speed V0 = 10 m / s. At what height h will the speed of the ball be half V0?
August 28, 2021 | education|
Ignoring the air resistance, we find that the movement of the ball up to the highest point of the trajectory is uniformly slowed down, with an acceleration g = 9.8 m / s2 directed vertically downward.
V = V0 – gt,
where V0 is the initial velocity of the ball, V0 = 10 m / s.
At height h, according to the problem statement: V = V0 / 2 = 10/2 = 5 m / s.
Ascent time to height h: t = (V0 – V) / g = (10 – 5) / 9.8 = 0.51 s.
Desired height h:
h = V0 t −g t ^ 2/2 = 10 × 0.51 – 9.8 × 0.51 ^ 2/2 = 3.83 m.
Answer: 3.83 m.
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