The ball is thrown vertically upward with an initial speed of 36 km / h. What is the maximum height it will climb?

The maximum lifting height of the ball can be calculated using the following formula (it can be derived from the path formula S = (V ^ 2 – V0 ^ 2) / 2a or using the energy conservation law En = Ek):

h = S = V0 ^ 2 / 2g, where V0 is the initial speed of the ball (according to the condition V0 = 36 km / h or 10 m / s), g is the acceleration of gravity (const, g = 10 m / s2).

Let’s do the calculation:

S = V0 ^ 2 / 2g = 10 ^ 2 / (2 * 10) = 100/20 = 5 m.

Answer: With an initial speed of 36 km / h, the ball can rise to a height of 5 meters.