The ball moves uniformly in a circle with a radius of 12 m with a centripetal

| February 19, 2021 | education

The ball moves uniformly in a circle with a radius of 12 m with a centripetal acceleration of 3 m / s ^ 2. What is the period of revolution of the ball in a circle?

R = 12 m.

a = 3 m / s2.

T -?

The period of rotation T is the time of one complete rotation.

Let us express the period T by the formula: T = L / V, where L is the circumference along which the ball moves, V is the ball’s rotation speed.

The length of the circle L is expressed by the formula: L = 2 * п * R, where п is the number pi, R is the radius of the circle.

Centripetal acceleration a is determined by the formula: a = V2 / R.

V = √ (a * R).

The formula for determining the period of rotation T will take the form: T = 2 * п * R / √ (a * R).

T = 2 * 3.14 * 12 m / √ (3 m / s2 * 12 m) = 12.56 s.

Answer: the period of rotation of the ball is T = 12.56 s.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.