The ball, rolling down from the inclined chute from the state of rest in 1 second

The ball, rolling down from the inclined chute from the state of rest in 1 second, has covered a path of 2 m. What path will it cover in the third second.

t = 1 sec
S1 = 2 m
S -?
To find the path that the ball will cover in the third second, we must subtract the path that the ball will cover in two seconds from the path that the ball will cover in 3 seconds.
S = S3 – S2
S3 = a * t ^ 2/2
we find the acceleration from the formula: S1 = a * t ^ 2/2, a = 2 * S1 / t ^ 2
a = 2 * 2/1 ^ 2 = 4 m / s ^ 2
S3 = 4 * 3 ^ 2/2 = 18 m – the path traversed by the ball in 3 seconds
S2 = 4 * 2 ^ 2/2 = 8 m – the path traversed by the ball in 2 seconds
S = 18 – 8 = 10 m – the path traversed by the ball in the 3rd second