The ball rolling down the hill at uniform acceleration with an initial speed of 1 m / s acquired

The ball rolling down the hill at uniform acceleration with an initial speed of 1 m / s acquired a speed of 7 m / s. What was the speed of the ball when it was half way?

The distance traveled by the body can be calculated using the formula:

S = (V² – V0²) / 2a, where S is the distance covered by the body, V is the final speed of the body (m / s), V0 is the initial speed of the movement (m / s), and is the acceleration of the body.

Full path traveled:

S = (V1² – V0²) / 2a, where V1 = 7 m / s, V0 = 1 m / s.

Half way:

0.5S = (V2² – V0²) / 2a.

(V1² – V0²) / 2a = 2 (V2² – V0²) / 2a.

V1² – V0² = 2V2² – 2V0².

72 – 12 = 2V2² – 2 * 12.

49 – 1 = 2V2² – 2.

50/2 = V2².

V2 = sqrt (25) = 5 m / s.