The ball rolls down the inclined chute from rest. In the first second, he goes 5 cm. Which way he will go in 5 seconds.

t1 = 1 s.

S1 = 5 m.

V0 = 0 m / s.

t2 = 5 s.

S2 -?

For uniformly accelerated movement, the path S traversed by the body is determined by the formula: S = V0 * t + a * t ^ 2/2, where V0 is the initial speed of movement, t is the time of movement, and is the acceleration of movement.

Since the ball moves from a state of rest V0 = 0 m / s, the formula will take the form: S = a * t ^ 2/2.

The traversed path in time t1 is expressed by the formula: S1 = a * t1 ^ 2/2.

Let us express the acceleration of the ball: a = 2 * S1 / t1 ^ 2.

S2 = a * t2 ^ 2/2 = 2 * S1 * t2 ^ 2/2 * t1 ^ 2 = S1 * t2 ^ 2 / t1 ^ 2.

S2 = 5 m * (5 s) ^ 2 / (1 s) ^ 2 = 125 m.

Answer: in the time t2 = 5 seconds, the ball will cover the path S2 = 125 m.