The ball, suspended on a thread 2 m long, swings. At the moment of passing the equilibrium position

The ball, suspended on a thread 2 m long, swings. At the moment of passing the equilibrium position, the speed of the ball is 3 m / s. What is the ball’s centripetal acceleration at this moment?

Centripetal acceleration is determined by the formula a = v ^ 2 / r
Substituting these values into the formula, we get: a = 3 ^ 2/2 = 4.5 (c / c ^ 2)
Answer: 4.5



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