The ball thrown upwards reaches a maximum height of 12.8m. What is the lifting time for the ball?

h = 12.8 m.
g = 9.8 m / s ^ 2.
V = 0 m / s.
t -?
The ball thrown upwards moves only under the action of gravity with a constant acceleration g.
g = (V -Vo) / t.
Since V = 0 m / s, then g = Vо / t.
t = Vо / g.
The path that the ball travels when climbing up is determined by the formula: h = (V ^ 2 -Vo ^ 2) / 2 * g.
h = Vo ^ 2/2 * g.
Vo = √ (2 * g * h).
t = √ (2 * g * h) / g.
t = √ (2 * 9.8 m / s ^ 2 * 12.8 m) / 9.8 m / s ^ 2 = 1.62 s.
Answer: the time for lifting the ball t = 1.62 s.