The ball was lowered from a height of 1.5 m from the floor. it hit the pores and bounced

The ball was lowered from a height of 1.5 m from the floor. it hit the pores and bounced upwards by 50 cm. Find the path and module to move the ball.

Given:

H1 = 5 meters – the height from which the ball was lowered;

H2 = 50 centimeters = 0.5 meters – the height to which the ball bounced.

It is required to determine the path S (meter) of the ball and its modulus of movement L (meter).

Let’s introduce a coordinate system, the origin of which will be the point from which the ball fell. Then, the path traversed by the ball will be equal to:

S = H1 + H2 = 5 + 0.5 = 5.5 meters.

At the beginning of the fall, the ball was at the point x = 5 meters, and after it bounced, at the point x1 = 0.5 meters. In this case, the module of movement will be equal to:

L = H1 – H2 = 5 – 0.5 = 4.5 meters.

Answer: the path traversed by the ball is 5 meters, the modulus of its movement is 4.5 meters.