The ball was thrown from the roof of the house at a speed of 20 m / s in the horizontal direction, find the speed of the ball
The ball was thrown from the roof of the house at a speed of 20 m / s in the horizontal direction, find the speed of the ball near the ground if the height of the house is 11.25 meters
To solve the problem, we will apply the law of conservation of energy.
But let’s start by analyzing the condition of the problem (let’s understand what is given to us).
It is known that the ball was thrown from the roof of the house and at that moment its speed was 20 m / s in the horizontal direction. We also know that the height of the house is 11.25 meters.
Let’s remember the law of conservation of energy:
mgh + mv0 ^ 2/2 = mv ^ 2/2.
From here we express the speed of the ball v and substitute the values and calculate:
v = √ (2 * g * h + v0 ^ 2) = √ (225 + 400) = √625 = 25 m / s.
Answer: 25 m / s.