The ball was thrown vertically upward at a speed of 5 m / s. What speed will it gain in 3 seconds?

The ball was thrown vertically upward at a speed of 5 m / s. What speed will it gain in 3 seconds? What is the movement and the distance traveled by the ball during this time?

Given:

V0 = 5 m / s – the speed with which the ball was thrown vertically upwards;

g = 10 m / s ^ 2 – acceleration of gravity;

t = 3 seconds.

It is required to determine the speed of the ball V in time t, as well as the path S and displacement L during this time.

Let’s calculate the flight time of the balloon to the maximum height:

t = V0 / g = 5/10 = 0.5 seconds.

Since the flight time is equal to the fall time, the ball will be in motion 2 * t = 2 * 0.5 = 1 second. That is, after 3 seconds it will lie on the ground and its speed will be equal to 0.

The maximum height to which the balloon will take off:

H = V0 * t – g * t ^ 2/2 = 5 * 0.5 – 10 * 0.5 ^ 2/2 = 2.5 – 1.25 = 1.25 meters.

Then the distance traveled is:

S = 2 * H = 2 * 1.25 = 2.5 meters.

Since the ball will fall to the same point from which it was thrown, the movement of the ball will be equal to 0.

Answer: after 3 seconds, the speed of the ball will be 0, the path it has traveled will be 2.5 meters, the movement of the ball will be 0.