The ball was thrown vertically upward with an initial speed of 20 m / s, the acceleration of gravity

The ball was thrown vertically upward with an initial speed of 20 m / s, the acceleration of gravity is 9.8 m / s. how long will it go up and what is the maximum lifting height?

Given:

v0 = 20 m / s – initial speed of the ball thrown vertically upwards;

g = 9.8 m / s2 – acceleration of gravity.

It is required to determine the lifting time of the ball t (seconds) and the maximum lifting height h (meter).

At maximum altitude, the speed of the ball will be zero. Then:

t = v0 / g = 20 / 9.8 = 2 seconds.

The maximum lifting height will be equal to:

h = v0 * t – g * t ^ 2/2 = 20 * 2 – 9.8 * 2 ^ 2/2 = 40 – 9.8 * 2 = 40 – 19.6 = 20.4 meters.

Answer: the lifting time of the ball will be 2 seconds, the maximum lifting height is 20.4 meters.