The bar being on the horizontal surface of the table was told a speed of 4 m / s. under the action of friction forces

The bar being on the horizontal surface of the table was told a speed of 4 m / s. under the action of friction forces, it moves with an acceleration of 1 m / s2. What is the distance traveled by the bar in 5 seconds?

The path covered by the bar:
S = V * t + аt² / 2, where S is the distance traveled (m), V is the speed of the bar (V = 4 m / s), t is the time the bar moves until it stops (s), and is the acceleration of the bar (movement bar equidistantly, a = 1 m / s²).
Time of movement of the bar to stop:
Vk = V + at, where Vk = 0 m / s.
t = V / a = 4/1 = 4 s (after 5 s, the bar will be at rest).
Let’s calculate the distance traveled by the bar:
S = V * t + аt² / 2 = 4 * 4 – 1 * 4² / 2 = 16 – 8 = 8 m.
Answer: The path traveled by the bar is 8 m.