The barge received a hole with an area of 400 cm2 at a depth of 2.5 m.

The barge received a hole with an area of 400 cm2 at a depth of 2.5 m. With what force should this hole be repaired in the bottom of the barge?

To find the value of the required force to seal the hole in the indicated barge, we apply the formula: F = P * S = ρw * g * h * S.

Data: ρw – water density (let’s take ρw = 1000 kg / m3); g – acceleration due to gravity (g ≈ 10 m / s2); h is the depth at which the hole is located (h = 2.5 m); S is the area of the hole (S = 400 cm2 = 400 * 10-4 m2).

Let’s perform the calculation: F = ρw * g * h * S = 1000 * 10 * 2.5 * 400 * 10-4 = 103 N.

Answer: The hole in the bottom of the indicated barge should be closed with a force of 1 kN.