The base AC of an isosceles triangle lies in a plane. Find the distance from point B to the plane if AB = 20cm, AC = 24cm

The base AC of an isosceles triangle lies in a plane. Find the distance from point B to the plane if AB = 20cm, AC = 24cm, and the dihedral angle between the planes ABC and is equal to 30 °

Since the triangle is isosceles and AB = 20 and AC = 24, we find the height of this triangle. ВK ^ 2 = AB ^ 2 – AK ^ 2.
AK is equal to half of the AС since the triangle is isosceles, then the height of the ВC = 16 cm.
We have given by condition the dihedral angle is the angle between the straight line ВK and the plane, the angle ВKO.
We need to find ВKO since the angle ВKO = 30 degrees and ВK = 16, then the leg lying opposite 30 degrees is equal to half the hypotenuse, that is:
BO = 1 6/2 = 8 centimeters
answer: BO = 8 centimeters.