The base of a rectangular trapezoid is 4cm and 7cm, one of the corners is 60 degrees. Find the larger side piece.
| May 8, 2021 | education
We draw from the top of an obtuse angle C we draw the height CH of the trapezoid ABCD.
The length of the segment DH, based on AD is equal to: DH = AD – AH = 7 – 4 = 3 cm.
Consider a right-angled triangle СНD, in which the angle СНD = 90 by construction, the angle НDС, by condition, is 60, then the angle DСН = 180 – 90 – 60 = 30.
The DH leg is located opposite an angle of 30, then its length is equal to half the length of the CD hypotenuse.
DH = CD / 2.
СD = 2 * DH = 2 * 3 = 6 cm.
Answer: The length of the larger side edge is 6 cm.
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