The base of a straight prism is a rhombus with diagonals of 16 and 30 cm. The large diagonal of the prism is 50 cm
The base of a straight prism is a rhombus with diagonals of 16 and 30 cm. The large diagonal of the prism is 50 cm. Calculate the area of the lateral surface of the prism.
Since there is a rhombus at the base of the prism, the diagonals AC and BD intersect at right angles and are halved at the point of intersection.
AO = CO = AC / 2 = 30/2 = 15 cm.
BO = DO = BD / 2 = 16/2 = 8 cm.
Let us determine the hypotenuse AD from the right-angled triangle AOD.
AD ^ 2 = AO ^ 2 + DO ^ 2 = 15 ^ 2 + 8 ^ 2 = 225 + 64 = 289.
AD = 17 cm.
In a rhombus, all sides are equal, then AB = BC = CD = AD = 17cm.
Consider a right-angled triangle AA1C and, by the Pythagorean theorem, define leg AA1.
AA1 ^ 2 = A1C ^ 2 – AC ^ 2 = 50 ^ 2 – 30 ^ 2 = 2500 – 900 = 1600.
AA1 = 40 cm.
Let us determine the area of the lateral surface.
Side = 4 * AB * AA1 = 4 * 40 * 17 = 2720 cm2.
Answer: S side = 2720 cm2.