The base of a straight prism is an isosceles triangle with a base of 10 cm

The base of a straight prism is an isosceles triangle with a base of 10 cm and a side side of 13 cm. Find the total surface area of the prism if its height is 2 cm.

Let’s calculate the area of the triangle lying at the base of the prism.
Let ABC be our triangle with base AB. Let h be the height from point C to face AB.
h ^ 2 = AC ^ 2 – (AB / 2) ^ 2 = 169 – 25 = 144. h = 12. Triangle area S = 12 * 10/2 = 60 sq. cm.
Let’s calculate the area of the side faces of the prism.
Multiply the perimeter of the triangle – the base of the prism by the height
T = (10 + 13 + 13) * 2 = 72 sq. Cm.
Prism surface area:
Q = 2 * S + T = 120 + 72 = 192 sq. Cm.
Answer: 192 sq. Cm.