The base of an isosceles trapezoid is 17 and 27 cm, and the acute angle is 60 “. Find its perimeter.

If we omit the heights from obtuse angles, then we divide the trapezoid into a rectangle and 2 identical (because the trapezoid is isosceles) right-angled triangles.
Consider a triangle.
We know one angle – 60 degrees. Hence the second angle = 30 degrees.
In a right-angled triangle opposite an angle of 30 degrees lies a side equal to 1/2 of the hypotenuse. The length of this side can be found as follows:
Since we have omitted the heights, the larger base = 27cm is divided by 17cm (side of the rectangle) and 2 identical segments:
(27-17) / 2 = 5cm
So the side opposite to the angle of 30 degrees is 5. Therefore, the hypotenuse is 5 * 2 = 10cm
Now we know all sides of the trapezoid.
Find the perimeter:
P = 27 + 17 + 10 + 10 = 64cm
Answer: P = 64cm



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