The base of the isosceles trapezoid is 2.1 and 7.5 and its diagonal is 6. Find the area.

Let’s build the height of the CH trapezium AВСD

Since the trapezium is isosceles, the height of the CH divides the larger base of the blood pressure into two segments, the length of the larger of which is equal to half the sum of the lengths of the bases of the trapezoid.

DН = (BP + BC) / 2 = (7.5 + 2.1) / 2 = 4.8 cm.

In a right-angled triangle ACН, according to the Pythagorean theorem, CH ^ 2 = AC ^ 2 – AH ^ 2 = 36 – 23.04 = 12.96.

CH = 3.6 cm.

Then Savsd = (BC + AD) * CH / 2 = (2.1 + 7.5) * 3.6 / 2 = 17.28 cm2.

Answer: The area of the trapezoid is 17.28 cm2.