The base of the isosceles triangle is 5 cm larger than the lateral side. Find the sides of the triangle

The base of the isosceles triangle is 5 cm larger than the lateral side. Find the sides of the triangle if the perimeter of the triangle is 35 cm.

Let ABC be an isosceles triangle. Since the sides of an isosceles triangle are equal, we denote AB and BC as x, then the base of AC is denoted as x + 5 (by condition, the base is 5 cm larger than the lateral side). Then:
x + x + x + 5 = 35;
3x = 35 – 5;
3x = 30;
x = 30/3;
x = 10.
AB = BC = x = 10 cm, AC = x + 5 = 10 + 5 = 15 cm.
Answer: AB = 10 cm, BC = 10 cm, AC = 15 cm.