The base of the triangle is greater than the midline, parallel to this base by 3 cm.

The base of the triangle is greater than the midline, parallel to this base by 3 cm. Then the sum of the midline and the base of the triangle will be equal to?

1. Vertices of triangle A, B, C. KE – middle line.

2. According to the problem statement AC – KE = 3 centimeters.

3. The length of the middle line, according to its properties, is 1/2 the length of the side parallel to it. That is, AC = 2KE.

4. Substitute AC = 2KE into the expression from point 2:

2KE – 2KE = 3;

KE = 3 centimeters.

AC = 2 x 3 = 6 centimeters.

5. KE + AC = 3 + 6 = 9 centimeters.

Answer: the total length of the middle line KE and the base of the AC triangle is 9 centimeters.