The base radius is 8 cm, the lateral surface area is half the base area. Find the complete surface of the cylinder?

First, let’s find the area of the base of the cylinder. Since its base is a circle, then:

Sosn. = πr ^ 2;

Sosn. = 3.14 42 = 3.14 * 16 = 50.24 cm2.

Since the area of the lateral surface is half the area of the base, then:

Sb.p. = Sosn. / 2;

Sb.p. = 50.24 / 2 = 25.12 cm2.

The total surface area of the cylinder is equal to the sum of the areas of its two bases and the area of the lateral surface:

S.p. = 2 S main. + Sb.p .;

S.p. = 2 50.24 + 25.12 = 100.48 + 25.12 = 125.6 cm2.

Answer: The total surface area of the cylinder is 125.6 cm2.