The bases of the trapezoid are 18 and 12, one of the sides is 6, the tangent of the angle between it and one of the bases

The bases of the trapezoid are 18 and 12, one of the sides is 6, the tangent of the angle between it and one of the bases is equal to the root of 2/4. find the area of the trapezoid

Consider a right-angled triangle ABE, which has a leg BE and a trapezoid height, and tgA = √2 / 4.

TgA = BE / AE = √2 / 4.

AE = 4 * BE / √2 = 2 * BE * √2.

By the Pythagorean theorem, AE^2 = AB^2 – BE^2 = 36 – BE^2.

(2 * BE * √2) 2 = 36 – BE^2.

8 * BE^2 = 36 – BE^2.

9 * BE^2 = 36.

BE^2 = 4.

BE = 2 cm.

Find the area of the trapezoid.

S = (BC + AD) * BE / 2 = (12 + 18) * 2/2 = 30 cm2.

Answer: S = 30 cm2.



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