The bases of the trapezoid are equal to 18 and 10, into which segments the diagonal divides the middle line of the trapezoid.

univerkov | September 2, 2021 | education

Let KM be the middle line of a trapezoid, the length of which is: KM = (BC + AD) / 2 = (10 + 18) / 2 = 14 cm.

Let us construct the length of the diagonal BD.

In the triangle ABD, the segment KH is the middle line, since the KN is parallel to AD, and the point K is the middle of the segment AB.

Then KH = AD / 2 = 18/2 = 9 cm.

Then MH = KM – KН = 14 – 9 = 5 cm.

Answer: The diagonal divides the middle line into 5 cm and 9 cm segments.

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